7x^2-50x-432=0

Solution for 7x^2-50x-432=0 equation:

7x^2-50x-432=0

a = 7; b = -50; c = -432;
Δ = b2-4ac
Δ = -502-4·7·(-432)
Δ = 14596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14596}=\sqrt{4*3649}=\sqrt{4}*\sqrt{3649}=2\sqrt{3649}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-50)-2\sqrt{3649}}{2*7}=\frac{50-2\sqrt{3649}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-50)+2\sqrt{3649}}{2*7}=\frac{50+2\sqrt{3649}}{14}
$